WebMathematics In a triangle, if r1 = 2 r2 = 3r3, then (a/b) + (b/c) + (c/a) is equal to Q. In a triangle, if r1 = 2r2 = 3r3, then ba + cb + ac is equal to 2475 46 BITSAT BITSAT 2008 Report Error A 6075 B 60155 C 60176 D 60191 Solution: Given that, r1 = 2r2 = 3r3 ∴ s−aΔ = s−b2Δ = s−c3Δ = kΔ Then, s−a = k,s− b = 2k,s−c = 3k ⇒ 3x −(a+ b+ c) = 6k Webr1=2r2=3r3 Then r1/6=r2/3=r3/2 =k using ratios Hence r1=6k, r2=3k r3=2k Hence using the property of solution of trianle the required triangle is equilateral. Please feel free to ask …
电工基础练习题03(有答案) - 搜档网
WebDec 25, 2024 · If r1, r2, r3 are the radii of the escribed circles of a triangle ABC and r is the radius of its in-circle then the root(s) asked Dec 25, ... If r1 = 2r2 = 3r3 then a+ b + c is equal to. asked Dec 25, ... jee mains +1 vote. 1 answer. In an equilateral triangle r:R:r1 is. asked Dec 25, 2024 in Trigonometry by SudhirMandal (53.8k points ... WebCorrect option is B) Given that r 1r 2r 3 are radii of ex-circles, we have the following relations r 1= s−aΔ,r 2= s−bΔ,r 3= s−cΔ where Δ is the area of the triangle ABC having lengths of the sides a,b,c and 2s= a+b+c Also given r 1=2r 2=3r 3 So r 2r 1=2 ⇒ s−as−b=2 ⇒s−b−2s=−2a ⇒s+b−2a=0 ⇒2s+2b−4a=0 ⇒a+b+c+2b−4a=0 ⇒c+3b−3a=0 ⇒c+3b−3a=0 ⇒c=3a−3b crystal lite ingredient list
If in triangle ABC,r1 =2r2 =3r3 ,D is the middle point of BC. Then …
WebStep 2: Determine the ratio. Since two angles are equal, the triangle is an isosceles right angle triangle and hence two sides will be equal. Therefore let sides a = k, b = k. Thus we have, by the converse of Pythagoras theorem. c = a 2 + b 2 = k 2 + k 2 = 2 k 2 c = 2 k. The ratio of a: b: c is 1 k: 1 k: 2 k o r 1: 1: 2. WebIf in a triangle ABC r 1=2r 2=3r 3, then the perimeter of the triangle is Medium View solution > In a triangle ABC, if r 1:r 2: r 3=2:4:6 then a:b:c= Medium View solution > View more Get … WebI On peut remarque que II = 2 surface du triangle D2 = D1 surface du rectangle . 2. ... ℘ = V. dl 2π 2π ℘ = −2R2 sin α 2 dα + 3 R2 cos α2 d ... V = q − = q (2-36) 4πε 0 r1 r2 4πε 0 r1 r2. Par définition d << r . Soit H la projection de B sur AM : AH = d cos = r2 − r1 ... dwr physio